hlo every one plzz solve this numerical
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sanju225:
it is value of Avogadro's no
yup its avogadro no.
no sakshi is right
it is from target 1
my book and the answer of her is correct
then....
there are 3elements in metanol
its methane buddy
CH4
ooo yes
Answers
Answered by
1
Heya
Atomic weight of methane is 12+4(1)=16g
16g make up one.mole
No.of moles of methane in 1.6g = 1.6/16 = 0.1 moles
In one mole of methane 6.022×10²³number of molevules are present.
In 0.1 mole 6.022×10²³×0.1 = 6.022×10²² molecules of methane
In one molecule, 10 electrons are present.
In 0.1 mole number of electrons present are 6.022×10²²×10 = 6.022×10²³
Hope it helps! ^_^
Atomic weight of methane is 12+4(1)=16g
16g make up one.mole
No.of moles of methane in 1.6g = 1.6/16 = 0.1 moles
In one mole of methane 6.022×10²³number of molevules are present.
In 0.1 mole 6.022×10²³×0.1 = 6.022×10²² molecules of methane
In one molecule, 10 electrons are present.
In 0.1 mole number of electrons present are 6.022×10²²×10 = 6.022×10²³
Hope it helps! ^_^
Answered by
0
Answer:
Heya
Atomic weight of methane is 12+4(1)=16g
16g make up one.mole
No.of moles of methane in 1.6g = 1.6/16 = 0.1 moles
In one mole of methane 6.022×10²³number of molevules are present.
In 0.1 mole 6.022×10²³×0.1 = 6.022×10²² molecules of methane
In one molecule, 10 electrons are present.
In 0.1 mole number of electrons present are 6.022×10²²×10 = 6.022×10²³
Hope it helps! ^_^
Please brainlest me the answer
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