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since we know that tan theta is equal to sin theta by cos theta and cot theta equal to cos theta by sin theta putting this value in given equation on taking lhs that is left hand side so we get
sin upon Cos A upon Sin A minus Cos A upon sin a +Cos A open Saina upon Cos A minus sin a upon Cos A that is equal to
sin square A upon Cos A in bracket x Sin A minus Cos A + cos squared upon sin x in bracket cos A minus sin a
on taking negative and taking LCM
we have
sin cube A minus cos cube A by Cos A into sin a jacket bracket with Sin A minus Cos A
as we know that the formula of a cube minus b cube equal to a minus b x square + b square + a b
since we have
Sin A minus Cos x sin square A + cos square A + sin a into Cos A by sin cos sin into cos x Sin A minus Cos A
p so we have sin square A + cos square A + sin into Cos A upon sin into Cos A on doing it separately we have sek into cosec A + 1 that is RHS so proved
sin upon Cos A upon Sin A minus Cos A upon sin a +Cos A open Saina upon Cos A minus sin a upon Cos A that is equal to
sin square A upon Cos A in bracket x Sin A minus Cos A + cos squared upon sin x in bracket cos A minus sin a
on taking negative and taking LCM
we have
sin cube A minus cos cube A by Cos A into sin a jacket bracket with Sin A minus Cos A
as we know that the formula of a cube minus b cube equal to a minus b x square + b square + a b
since we have
Sin A minus Cos x sin square A + cos square A + sin a into Cos A by sin cos sin into cos x Sin A minus Cos A
p so we have sin square A + cos square A + sin into Cos A upon sin into Cos A on doing it separately we have sek into cosec A + 1 that is RHS so proved
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