hlo friends..
if v is the volume and s is the surface are cubiod of dimensions a,b,c then prove that 1/v=2/5(1/a+1/b+1/c)
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a , b , c are dimensions of the
cuboid.
S = 2 ( ab + bc + ca )
V = abc
RHS = 2/S(1/a + 1/b + 1/c )
= 2/[ 2( ab+bc+ca )] { 1/a+ 1/b + 1/c}
= 1/( ab+ bc +ca ) {( bc + ac + ab )/abc }
= 1/abc
= 1/V
= LHS
Hope it may helps you
cuboid.
S = 2 ( ab + bc + ca )
V = abc
RHS = 2/S(1/a + 1/b + 1/c )
= 2/[ 2( ab+bc+ca )] { 1/a+ 1/b + 1/c}
= 1/( ab+ bc +ca ) {( bc + ac + ab )/abc }
= 1/abc
= 1/V
= LHS
Hope it may helps you
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