Question

hlo frnds
pls answer my question
÷÷÷÷÷÷÷÷÷÷÷÷÷÷÷÷÷÷÷
in a factorythe productino. of motor bikes was 40000 in a particular year ,which rose to48,400 in two years .find the rate of growth per annum ,if it was uniform during two years
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Answer 1

$let \: the \: rate \: of \: growth \: be \: r\%p.a$
$production \: of \: scooter \: after \: 2years$
$48400 = 40000 \: {(1 + \frac{r}{100} )}^{2}$
${(1 + \frac{r}{100}) }^{2} = \frac{484}{400}$
${(1 + \frac{r}{100} )}^{2} = { (\frac{22}{20}) }^{2}$
$1 + \frac{r}{100} = \frac{22}{20}$
$\frac{r}{100} = \frac{22}{20} - 1 = \frac{22 - 20}{20} = \frac{1}{10}$
$\frac{r}{100} = \frac{1}{10}$
$r = \frac{100}{10} = 10$
$the \: rate \: of \: growth \: = 10\%$

Answer 2

answer is 10%
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