Hlo guys
please answer question
The diagonals of a rectangle ABCD intersect at O if angle BOC is equal to 60 degree find angle ODA
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Answer:
In triangle BOC,
ang BOC +ang OCB+ang OBC= 180°
60°+2 ang OBC= 180° [as triangle OBC is an isocelestriangle, the base angles are equal]
2 ang OBC=180°-60
=120
ang OBC=120/2 °
ang OBC=60°
ang OBC=ang ODA
ang ODA=60°
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