Question

hlo guys... please solve this equation I am not able to find answer.. question 1. iv) part

Answer 1

2x2+7x+3=0 or 2x2+6x+x+3 =0 or 2x(x+3)+1(x+3)=0 or (x+3)(2x+1)=0 or x +3=0 x=−3 =======Ans 1 or 2x+1=0 or 2x=− ...

Answer 2

Given Equation is 2x^2 + x + 4 = 0

$= \ \textgreater \ x^2 + \frac{x}{2} + 2 = 0$

$= \ \textgreater \ x^2 + \frac{x}{2} + \frac{1}{4} - \frac{1}{4} + 2 = 0$

$= \ \textgreater \ (x + \frac{1}{2} )^2 - \frac{1}{4} + 2 = 0$

$= \ \textgreater \ (x + \frac{1}{2} )^2 = -2 + \frac{1}{4}$

$= \ \textgreater \ (x + \frac{1}{2})^2 = \frac{-7}{4}$

$x + \frac{1}{2} = \frac{ \sqrt{7} }{2}$


Now,

$x + \frac{1}{2} = \frac{ \sqrt{7} }{2}$

$x = \frac{ \sqrt{7} - 1 }{2}$



$x + \frac{1}{2} = \frac{- \sqrt{7} }{2}$

$x = \frac{- \sqrt{7} - 1 }{2}$



Hope this helps!