Question

hlo guys please solve this question . it's a urgent qno.27​

Answer 1

Answer:

STEP BY STEP EXPLANATION GIVEN IN THE ABOVE PIC

Answer 2

$yur \: answer \\ \\ y = \sqrt{x} + \frac{1}{ \sqrt{x} } \\ \\ differentiate \: \: both \: \: sides \: \: w.r.t \: \: x \\ \\ \frac{dy}{dx} = \frac{1}{2 \sqrt{x} } + \frac{d( \frac{1}{ \sqrt{x} } )}{dx} \\ \\ \frac{dy}{dx} = \frac{1}{2 \sqrt{x} } - \frac{x {}^{ \frac{ - 3}{2} } }{2} \\ \\ \frac{dy}{dx} = \frac{1}{2 \sqrt{x} } - \frac{1}{2x \sqrt{x} } \\ \\ \frac{dy}{dx} = \frac{ \sqrt{x} }{2x} - \frac{1}{2x \sqrt{x} } \\ \\ \frac{dy}{dx} = \frac{1}{2x} ( \sqrt{x} - \frac{1}{ \sqrt{x} } ) \\ \\ 2x \frac{dy}{dx} = (2 \sqrt{x} - ( \sqrt{x} + \frac{1}{ \sqrt{x} } )) \\ \\ 2x \frac{dy}{dx} = (2 \sqrt{x} - y) \\ \\ 2x \frac{dy}{dx} + y = 2 \sqrt{x}$