Math, asked by Anonymous, 1 year ago

Hlo guys.......
plz solve this question......​

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Answers

Answered by bhanurajora123
1

Answer:

Step-by-step explanation:

For infinite many solution

a1/a2=b1/b2=c1/c2

3/m+n=4/2(m-n)=-12/-(5m+1)

6(m-n)=4(m+n)

6m-6n=4m+4n

2m-10n=0. EQ(1).

4(5m+1)=-24(m-n)

10m+4=-24m+24n

34m-24n=-4. EQ(2).

Eliminate EQ (1)&(2).

n=-2/73

&

m=-10/73

Answered by ItzAaryan
0

Ur ans is.......

m= -10/73..

...

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