Question

hlo guys
tell the answer​

Answer 1

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{Principal=30000\:rupees}}}$

$\green{\tt{\therefore{Amount=39930\:rupees}}}$

$\green{\tt{\therefore{Compound\:Interest=9930\:rupees}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{\underline \bold{Given :}} \\ \tt: \implies Simple \: Interest(S.I) =6000\: rupees \\ \\ \tt: \implies Time(t) = 2\: years \\ \\ \tt: \implies Rate\% = 10\% \\ \\ \red{\underline \bold{To \: Find :}} \\ \tt: \implies Principal(p) = ?\\\\\tt: \implies Amount(A) = ?\\\\\tt: \implies Compound\:Interest(C.I) = ?$

• According to given question :

$\bold{As \: we \: know \: that} \\ \tt: \implies S.I = \frac{p \times r \times t}{100} \\ \\ \tt: \implies 6000 = \frac{p \times 10 \times 2}{100} \\ \\ \tt: \implies 6000 \times 5 = p \\ \\ \green{\tt: \implies p = 30000 \: rupees} \\ \\ \tt \circ \: Principal = 30000 \: rupees \\ \\ \tt \circ \: Rate\% = 10 \% \\ \\ \tt \circ \: Time = 3 \: years \\ \\ \bold{As \: we \: know \: that} \\ \tt: \implies A= p(1 + \frac{r}{100} )^{t} \\ \\ \tt: \implies A= 30000 \times (1 + \frac{10}{100} )^{3} \\ \\ \tt: \implies A = 30000 \times (1 + 0.1)^{2} \\ \\ \tt: \implies A= 30000 \times 1.331 \\ \\ \green{\tt: \implies A=39930 \: rupees} \\ \\ \bold{For \: Comound \: Interest} \\ \tt: \implies C.I= A - p \\ \\ \tt: \implies C.I = 39930 - 30000 \\ \\ \green{\tt: \implies C.I =9930\: rupees}$

Answer 2

bq

$\tt{\huge{\purple{ .................. }}}$

QUESTION :

The simple interest on a certain someone of money at 10 % per annum is Rs. 6000 in 2 years

Find :

1. The Sum

2. The amount due at the end of 3 years at the same rate of interest compounded annually.

3. The compound Interest Earned in 3 years.

SOLUTION :

PART 1 :

We know that :

SI = { PTR } / 100

Where,

P is the principle amount.

T is the required time period.

R is the rate per annum.

Substituting these above values into the formula,

6000 = 20 P / 100

=> P / 5 = 6000

=> P = Rs. 30,000

PART 2 :

Now, we know that in Compound Interest compounded annually :

A = P ( 1 + r / 100 ) ^ t

Here ,

A is the amount.

P is the principle

R is the rate per annum.

Substituting the required values :

A = 30,000 × ( 11 / 10 ) ^ 3 = 30 × 1331 = Rs. 39930

PART 3 :

We know that Compound Interest = Amount - Principle

=> Rs. 39930 - Rs. 30000

=> Rs. 9930

ANSWER :

1. Rs 30,000

2. Rs. 39930

3. Rs. 9930