Question

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Answer 1

Consider the infinitesimly small length dx at a distance x.

So speed of this part is ωx.

Induced small emf = Bωx dx (since emf = vBl)

The positive charges of the rod will be pushed towards O by the magnetic field. Thus, the rod may be replaced by a battery of emf source with the positive terminal towards O. The equivalent circuit diagram is shown in figure. The circular loop joins A to C by a resistance less path. The current in the resistance R is

I=Bωl2/2

Answer 2

Answer:

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