Math, asked by Anonymous, 6 months ago

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Here The question ;

Five year ago Nuri was thrice as old as soon . Ten year later . Nuri will be twice as old as Sonu . How old are NURI AND SONU are .


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Answered by Anonymous
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Answer:

{\tt{\red{\underline{\large{Question}}}}}

Five year ago Nuri was thrice as old as soon . Ten year later . Nuri will be twice as old as Sonu . How old are NURI AND SONU are .

{\tt{\green{\underline{\large{Answer}}}}}

Let the present age of Nuri  = x year

And present age of Sonu = y year

Five years ago

Age of Nuri = x–5 years

Age of Sony = y–5 years

Nuri was thrice as old as Sonu

x−5 = 3(y–5)

x–5 = 35–15

x–3y = −15+5

x–3y= −10                  ………..(1)

Ten years later,

Age of Nuri  =x+10

Age of Sonu =y+10

Nuri will be twice as old as Sonu.

x+10 = 2(y+10)

x+10 = 2y+20

x–2y = 10                      ………..(2)

x–3y = −10                    .………..(1)

Now we will subtract equation (1) from equation (2), and we will get

Y=20

Plug this value in equation first, we get

x−3×20 = −10

x = 60–10

x = 50

Hence, Age of Nuri =50 years

Age of Sonu =20 years

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