Math, asked by shubhamkumar81, 1 year ago

Hlo listen Plzzzz
how to find value of 11c3.
it's related to binomial theorem class 11

Answers

Answered by aRKe09
2
11c3 = 11!/[3!*(11-3)!] = 11!/(3!*8!)

 \frac{fact(11)}{fact(3) \times fact(11 - 3)} \\--> fact(n) = n \times (n - 1) \times (n - 2)...............3 \times 2 \times 1 \\ = \frac{11 \times 10 \times 9 \times 8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1 }{(3 \times 2 \times 1)( 8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1)} \\ = 11 \times 5 \times 3 \\ = 165
if you have any doubts comment below
Answered by manasitiwari2308
0
hope it helps you...........
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