Hlo mate anyone solve my question please. Fast its urgently
Which term of AP:121,117,113,......., is its first negative term?
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Answered by
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a=121, d=-4, let an=0
an=a+(n-1)d
0=121+(n-1)(-4)
-121=-4n+4
-125=-4n
n=31.25
since n has to be a whole no., therefore, the ans is 32 ( the no. next to 31.25)
hence the 32nd term is the first negative term
an=a+(n-1)d
0=121+(n-1)(-4)
-121=-4n+4
-125=-4n
n=31.25
since n has to be a whole no., therefore, the ans is 32 ( the no. next to 31.25)
hence the 32nd term is the first negative term
Answered by
0
Answer:
32nd term
Step-by-step explanation:
AP is 121,117,113...
First term a = 121
Common difference = 117 - 121
= -4.
Let the nth term of the AP is the first negative term.
an < 0.
a + (n - 1) * d < 0
121 + (n - 1) * (-4) < 0
121 - 4n + 4 < 0
125 - 4n < 0
125 < 4n
4n > 125
n > 125/4
n > 31.25
Since, the term cannot be in decimal.So, n = 32.
Hence, the first negative term is 32nd term.
Hope it helps you
#Bebrainly
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