Question

Hlo....mate

Merry Christmas to all




In a class there are 8 boys and 5 girls. In how many ways can they sit in a row so that no two girls sit together?



Answer fast

Answer 1

Answer:

609638400

Step-by-step explanation:

The seating arrangement will be :

_B_B_B_B_B_B_B_B_

(i)

8 boys can sit in any of the 8 places.

= P(8,8)

= 8!

= 40320.

(ii)

5 girls can sit any of the 9 places.

= P(9,5)

= 9!/(9 - 5)!

= 9!/4!

= 15120.

Hence,total number of ways in which no two girls sit together:

= 40320 * 15120

= 609638400.

---------------------------- Merry Christmas -------------------------------

Hope it helps!