Math, asked by Anonymous, 11 months ago


hlo mates

A rhombus sheet whose perimeter is 32 m and whose one diagonal is 10 m long,is
painted on both sides at the rate of Rs 5 per m². Find the cost of painting.
 \mathfrak \red{p} \blue{l}  \green{z} \:  \pink{give}  \: \purple{answer}
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Answers

Answered by ItzSmartyYashi
47

Refer to attachment..

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\huge{\underline{\mathbb{\pink{Thankyou}}}}

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Answered by 3CHANDNI339
48

 \underline \mathbb{SOLUTION}

 \bold\green{\underline{Given\:that}}

》Perimeter of rhombus = 32 m.

 \bold\green{\underline{We\:know}}

》Perimeter = 4a

 \bold\green{\underline{Then\:ATQ:-}}

 =  > 4a = 32

 =  > side = 8m

 \boxed {SIDE(AB)= 8m}

》Diagonal AC = 10m

And,

》OA = 1/2 AC

 =  >  \frac{1}{2}  \times 10

 =  > side = 5m

 \boxed {SIDE(OA)= 5m}

\bold\green{\underline{From\:Pythagoras:-}}

 =  > ob =  {ab}^{2}  -  {oa}^{2}

 =  > ob =  \sqrt{ {8}^{2}  -  {5}^{2} }

 =  > ob =  \sqrt{64 - 25}

 =  > ob =  \sqrt{39} m

 \underline \mathbb{NOW,}

》BD = 2 OB = 2√39 m

 =  > area \: of \: sheet =  \frac{1}{2}  \times bd \times ac

 =  >  \frac{1}{2}  \times 2 \sqrt{39}  \times 10 = 10 \sqrt{39}  {m}^{2}

》COST OF PAINTING at rate of 5 metre square

 =  >  \frac{1}{2}  \times 2 \sqrt{39}  \times 10

  =  > cost = rs.625

 \boxed {COST= Rs.625}

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