Question

hlo mates pehle ye solve kardo phir so jana ☺thank u

Answer 1

Answer:

EL = 2 BL

Step-by-step explanation:

From figure:

M is the mid-point of CD.

In ΔEMD and ΔBMC

⇒ ∠MDE = ∠MCB

⇒ DM = CM

⇒ ∠DME = ∠CMB {vertically opposite angles are equal}

⇒ ΔEMD ≅ ΔBMC

⇒ DE = BC {c.p.c.t}

In ΔAEL and ΔCBL,

⇒ ∠ALE = ∠CLB

⇒ ∠AEL = ∠CBL

⇒ ΔAEL ~ ΔCBL

⇒ AE/BC = EL/BL

⇒ 2 BC/BC = EL/BL

⇒ 2 = EL/BL

⇒ 2 BL = EL.

***************************** Happy Makar Sankranthi  *************************

Hope it helps!