Question

HLO MATES

please ANS THIS Question.that is in the attachment....

best ans will be marked as brainleist..

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Answer 1

(15).

Let the sum be 'x'.

Given, Time = 3 years, R = 15%.

(i)

We know that S.I = PRT/100

                                = (x * 15 * 3)/100

                                = 45x/100.

(ii)

We know that CI = P(1 + r/100)^n - P

                            = x(1 + 15/100)^3 - x

                            = (12167x/8000) - x

                            = 4167x/8000.

Now,

Given Difference between SI and CI is 283.50.

⇒ (4167x/8000) - (45x/100) = 283.50

⇒ (4167x/8000) - (9x/25) = 283.50

⇒ 4167x - 3600x = 2268000

⇒ 567x = 2268000

⇒ x = 4000.

Therefore, the sum is 4000.

Hope this helps!

Answer 2

let the required sum be ' p '

Given , rate = 15 % p.a , time = 3 yrs

Find the simple interest :
----------------------------------

simple interest = ( p × r × t ) / 100

= (p × 15 × 3 )/ 100 = 45p / 100

Find the amount :
------------------------

amount = p [ 1 + ( r / 100 ) ]^t

amount = p [ 1 + ( 15/ 100 ) ]^3

amount = p ( 115 / 100 )^3

= p ( 23 / 20 )^3

= p ×( 23× 23× 23 )/ 20 × 20 ×20

= 12167p / 8000

Find the C.I :
-----------------

compound interest = amount - principal

C.I = (12167p / 8000 ) - p

C.I = (12167p - 8000p) / 8000

= ₹4167p /8000

Given , difference = ₹ 283.50

difference = C.I - S.I

283.50 = (4167p/8000) - ( 45p /100 )

283.50 × 800000 = ( 416700p -360000p )

226800000 = 56700p

2268000 = 567p

p = 2268000 ÷ 567 => p = ₹ 4000

therefore , the required sum = ₹4000

Answer : sum = ₹4000

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