hlo ples solve 106 and 107....
pless its urgent
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∆ABC is right - angled at A.
so, BC is definitely hypotenuse.
let AB is base and AC is altitude of ∆ABC.
given, AB = 6cm , BC = 10cm and AC = 8cm
now, area of triangle ∆ABC = 1/2 × base × altitude
= 1/2 × length of AB × length of AC
= 1/2 × 6cm × 8cm = 24cm²
hence, area of ∆ABC = 24cm²
area of ∆ABC = 1/2 × length of AB × length of AC = 1/2 × length of BC × length of AD
=> 6cm × 8cm = 10cm × length of AD
=> 24/5= length of AD
hence, length of AD square is 23.04 cm ( 4.8 × 4.8)
so a) answer is right ☺️
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