hlo plz give answer guyzzzzzzzz
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Distance covered in 8 s
S = ut + 0.5at^2
= 0 + (0.5 × 5 × 8^2)
= 160 m
Velocity after 8 s
v = u + at
= 0 + (5 × 8)
= 40 m/s
Distance covered in 4 s when it is moving with constant velocity is
Distance = Velocity × Time
= 40 m/s × 4 s
= 160 m
Total distance covered by car in 12 seconds
= 160 m + 160 m
= 320 m
S = ut + 0.5at^2
= 0 + (0.5 × 5 × 8^2)
= 160 m
Velocity after 8 s
v = u + at
= 0 + (5 × 8)
= 40 m/s
Distance covered in 4 s when it is moving with constant velocity is
Distance = Velocity × Time
= 40 m/s × 4 s
= 160 m
Total distance covered by car in 12 seconds
= 160 m + 160 m
= 320 m
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