Question

hlo ....



plzzz solve question number 6 nd 7✌️​✌️​

Answer 1

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$r = 5cm$

Step-by-step explanation:

Let the radius of the circle be r.

In ∆AOM

OM is perpendicular on AB.

$AM = \frac{1}{2} AB \\ = \frac{1}{2} AB \\ = \frac{1}{2} \times 8 \\ = 4cm \\ OM = (r - 2cm) \\ OA = r \\ {OA}^{2} ={AM}^{2}+{OM}^{2}$

${r}^{2} = {4}^{2} + {(r - 2)}^{2}$

$=16+{r}^{2}-2×r×2+{2}^{2}$

$OA=16-4r+4$

$OA=20-4r \\</p><p>4r=20 \\</p><p>r=5cm$

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Answer 2

Yuvii I think it's help you ❤️❤️❤️❤️❤️