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Answered by
12
Answer:
The time required to come to rest is 1 second
Explanation:
The displacement is given as:
x=10+6t-3t^2
Differentiate it wrt to time (t) we get,
dx/dt=6-6t
v=6-6t
At rest velocity =0
0=6-6t
t=1
hence the time required is 1 second
Answered by
1
THE GIVEN EQUATION IS 》》
NOW -☆differentiation☆
THE TIME TAKEN BY PARTICLE TO BE IN REST.
AFTER ONE SECOND THE PARTICLE WILL BE AT REST.
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