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Show relationship between Electric field and Potential difference .
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1
Answer:
The relationship between potential and field (E) is a differential: electric field is the gradient of potential (V) in the x direction. This can be represented as: Ex=−dVdx E x = − dV dx . Thus, as the test charge is moved in the x direction, the rate of the its change in potential is the value of the electric field
Answered by
1
Answer:. V = Edr
Explanation:
E= kq/rr
And V =kq/r
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