Question

hloooo....


Derive vector form of INTENSITY OF ELECTRIC FIELD.​

Answer 1

Answer:

....

Explanation:

$\overrightarrow{E} = \frac{\overrightarrow{F}}{Q_o}......$(by definition)

By Coulombs' Law:

$\overrightarrow{F} = \frac{kQQ_o}{|r|^3} \overrightarrow{r} \\=\frac{kQQ_o}{|r|^2}\hat{r}$

So put this in the electric field formula:

$\overrightarrow{E} = \frac{kQ}{|r|^2} \hat{r}$

Here, r cap is unit vector in direction of position vector of point and

$k=\frac{1}{4\pi \epsilon_0}$

Answer 2

above answer is correct.....✌