Question

Hlp me to solve this qstn..

Answer 1

i think the sum of first n odd number is
2n+1
if helps tjen mark as brainliest

Answer 2

Answer:

The sum of the first n odd numbers is (c) n^2.

Step-by-step explanation:

The first n odd natural numbers are 1, 3, 5, ... 2n-1.

This forms an arithmetic progression with first term 1, common difference 2 and last term (2n-1).

The sum is given by Sum = 1+3+5+...+(2n-1).

Using Sum = n (First term + Last term)/2,

So, we get Sum = n (1+2n-1)/2,

Which then simplifies to Sum = n^2.