Question

Hlw everyone up here!!
Maths//--
QUESTION:- For p(x) = (x-1) (x-2) Find p(2)

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Answer 1

$p(x) = {x}^{2} - 2x - 1x +2 \\ p(x) = x(x - 2) - 1(x - 2) \\ p(x) = x - 1 = 0 \: \: \: \: \: x - 2 = 0 \\ p(x) = x = 1 \: \: \: \: \: x = 2 \: \: are \: the \: zeroes \: of \: the \: polynomial \\ p(2) = (2 - 1)(2 - 2) \\ p(2) = (1)(0) \\ p(2) = 0 \\ i \: hope \: its \: help \: you \: \\ plz \: mark \: me \: as \: a \: brainest$

Answer 2

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⏩Limit the information in a paragraph.

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⏩ Relevance of ideas

⏩ Appropriateness of words chosen ⏩Correctness of grammatical structures, vocabulary