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12th class
subject--chemistry
chapter--solution
200 cm3 of an aquous solution of a protein contains 1.26 g of the protein. The osmotic pressure of such a solution at 300k is found to be 2.57× 10-3 bar. Calculate the molar mass of the protein.
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Answers
Answered by
2
Heya,
Answer to your question is:-
According to Van't Hoff equation,
π = cRT
= n/v RT
= W(B)RT/M(B)V
M(b) = W(B)RT/ πV
V=200cm³=0.20 L
W(B)=1.26 g
T=300K
R= 0.083 L bar K^-1 mol^-1
π= 2.57× 10^-3 bar
Therefore, M(B)=
1.26×0.083×300
______________
2.57×10^-3×0.20
=>【 M(B)= 61039 gmol^-1】 ANSWER...
HOPE THIS HELPS YOU:-))
@Ashu
Answer to your question is:-
According to Van't Hoff equation,
π = cRT
= n/v RT
= W(B)RT/M(B)V
M(b) = W(B)RT/ πV
V=200cm³=0.20 L
W(B)=1.26 g
T=300K
R= 0.083 L bar K^-1 mol^-1
π= 2.57× 10^-3 bar
Therefore, M(B)=
1.26×0.083×300
______________
2.57×10^-3×0.20
=>【 M(B)= 61039 gmol^-1】 ANSWER...
HOPE THIS HELPS YOU:-))
@Ashu
aasifasif526gmailcom:
thank you very much ashu
my pleasure:-)
нη η
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0
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