Question

♥hlw frnds plzz help♥
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2 cubes each of volume 64 cm3 are joined end to end . Find the surface area of resulting cuboid???
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Answer 1

Answer:

volume of cube=64

side of cube=3√64=4m

so

new length of resulting cuboid=4+4=8cm

new breadth=4cm

height=4cm

Surface area of cuboid=2(lb+bh+lh)

SA=2(32+16+32)

SA=2( 80)

SA=160CM2

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Answer 2

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The Volume (V) of each cube is = 64 cm^3

This implies that a3 = 64 cm^3

∴ The side of the cube, i.e. a = 4 cm

Also, the breadth and length of the resulting cuboid will be 4 cm each while its height will be 8 cm.

So, the surface area of the cuboid (TSA) = 2(lb + bh + lh)

Now, by putting the values, we get,

= 2(8×4 + 4×4 + 4×8) cm^2

= (2 × 80) cm^2

Hence, TSA of the cuboid = 160 cm^2

Hope it's Helpful.....:)