Question

hlw gys
find the greatest no. on. which dividing 1656 and 2037 leaves a remainder 6 on each case..​

Answer 1

numbers = 1656 , 2037

=> a = 1656 + 6 = 1662

=> b = 2037 + 6 = 2043

The number will be the H.C.F of a and b.

1662 = 2 × 3 × 227

2043 = 3² × 227

H.C.F(a,b) = common terms with lowest power

=> H.C.F(a,b) = 227 × 3

=> H.C.F(a,b) = 681

Hence, Your answer is 681

Answer 2

Step-by-step explanation:

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♡ ↪☛ The greatest number which on dividing 1657 and 2037 leaves remainders 6 and 5 respectively, is: [A]. = H.C.F. of 1651 and 2032 = 127.

♡

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