Question

hlw pls solve this fast❣️​

Answer 1

Answer:

x = $\frac{1}{3}$ and y = $\frac{11}{2}$

Step-by-step explanation:

4. 2x + 1 = $\frac{2}{3}$ + 3x

2x + 1 = $\frac{2 + 9x}{3}$                                          (Taking LCM)

3 (2x + 1) = 2 + 9x

6x + 3 = 9x + 2

9x - 6x = 3 - 2

3x = 1

x = $\frac{1}{3}$

5. $\frac{y}{3}$ + $\frac{1}{3}$ = $\frac{y}{4}$ - $\frac{1}{8}$

Taking LCM

$\frac{y+1}{3}$ = $\frac{2y-1}{8}$

8 (y + 1) = 3 (2y - 1)

8y + 8 = 6y - 3

8y - 6y = - 3 - 8

2y = -11

y = $\frac{11}{2}$

Hope this is correct :)