Question

Hlww......
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A question for u.....
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Prove this:
(sec A-cosA)(cot A+tanA)=secAtanA​

Answer 1

Answer:

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LHS=(secA-cosA) * (cotA+tanA)

=(1/cosA - cosA) * cosA/sinA + sinA/cosA)

=(1-cos^2A)/cosA * (sin^2A + cos^2A ) / sinA cosA)

={(sin^2A) /cosA}*(1/sinA cosA)

=sinA/cos^2A = (sin A/cosA)*(1/cosA)=tanA*secA=RHS

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