Question

hmare samvidhan nirmata ne Bharat ke rajyo ka Sangh ghoshit kiyu kiya​

Answer 1

Explanation:

Explanation:

Question

A force of 5 N acting on a body at an Angle of 30° with horizontal direction displaces it horizontally through a distance of 6 m Calculate the work done.

\rule{250}{2}

We know : Work Done = Fs × cosθ

Where

F = Force

s = Displacement

θ = Angle Formed

Work Done = Fs × cosθ

⇒ Work Done = F × s × cosθ

⇒ Work Done = 5 × 6 × cosθ

⇒ Work Done = 30 × cosθ

Note : We will Have θ = 30° as it is given Angle Formed is equal to 30°

⇒ Work Done = 30 × cos 30°

⇒ Work Done = 30 × \rm{\dfrac{\sqrt{3}}{2}}

2

3

⇒ Work Done = 15 × √3

⇒ Work Done = 15 × 1.732

⇒ Work Done = 25.98 JExplanation:

Question

A force of 5 N acting on a body at an Angle of 30° with horizontal direction displaces it horizontally through a distance of 6 m Calculate the work done.

\rule{250}{2}

We know : Work Done = Fs × cosθ

Where

F = Force

s = Displacement

θ = Angle Formed

Work Done = Fs × cosθ

⇒ Work Done = F × s × cosθ

⇒ Work Done = 5 × 6 × cosθ

⇒ Work Done = 30 × cosθ

Note : We will Have θ = 30° as it is given Angle Formed is equal to 30°

⇒ Work Done = 30 × cos 30°

⇒ Work Done = 30 × \rm{\dfrac{\sqrt{3}}{2}}

2

3

⇒ Work Done = 15 × √3

⇒ Work Done = 15 × 1.732

⇒ Work Done = 25.98 J