Question

ho: 70)
1. On a certain Sunday, stall A sold 308 burgers and stall B
sold 3 times as many burgers as stall A, C sold 85 fewer than
stall B. How many burgers did stall C sell?
Solution:
Number of burgers sold at stall A = 308​

Answer 1

Answer:

You must have knowledge to form simultaneous equations to solve this one.

Let x be hamburgers and y be cheeseburgers so that

x+y=597 (combined total of sold burgers)—————————(1)

x-y=53 (53 less cheeseburgers sold than hamburgers)————(2)

Solve the equations by elimination method. Add equation (1) to (2)

2x+0=650; x=325

Bonus: lets us find number of cheeseburgers sold .

And by substituting x for 325 in either of the two equations

y+325=597;y=272

That is it! Simple and clear.

Solve this with same method