Ho can you please answer me fast
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hlw...
here is ur answer.. ^↓^
(x+4)(x+2)
using identity -
(x+a)(x+b)=x²+(a+b)x+ab
x²+(4+2)x+(4)(2)
x²+6x+8
@π$w£® is ^↓^
x²+6x+8✋✋✋✋
hope it helps uh..!!✌✌✌✌
please mark it as brainliest...☺☺☺
here is ur answer.. ^↓^
(x+4)(x+2)
using identity -
(x+a)(x+b)=x²+(a+b)x+ab
x²+(4+2)x+(4)(2)
x²+6x+8
@π$w£® is ^↓^
x²+6x+8✋✋✋✋
hope it helps uh..!!✌✌✌✌
please mark it as brainliest...☺☺☺
aayushi4643:
oh thanks
Answered by
0
8
[x+4] [ x+2]
the formula is 1st term of 1st expression into 2nd expression + 2nd term of 1st expression into second term
that is
x[x+2]+4[x+2]
x ²+2x+4x+8
x²+6x+8 =sol
9
[x²+3] [ x²-8]
x²[x²-8]+3[x²-8]
x power 4 -8x²+3x²-24
x power 4 -5x²-24=sol
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