Question

HO CHEMI 41. In a vessel 4 g of O2,4 g of H2,4 g of N2 and 4 g of Cl, are present. Which of these gases has highest number of atoms? (A) 02 (B). H2 (C) N2 (D). Cl2​

Answer 1

Answer

B

Explanation:

No of moles ( O2)= 4/32=0.125

No. of moles (H2)=4/2=2

No. of moles (N2) = 4/28 =0.143

Answer 2

Given: In a vessel 4 g of O2,4 g of H2,4 g of N2 and 4 g of Cl, are present.

To find: We have to find which gas have highest number of atoms.

Solution:

Number of atoms in a compound is directly proportional to the number of moles.

So, the gas which will have highest number of moles will possesses highest number of atoms.

Number of moles of oxygen is 4/32=0.125

Number of moles of hydrogen is 4/2=2

Number of moles of nitrogen is 4/28=0.142

Number of moles of chlorine is 4/35=0.114

Thus hydrogen gas have highest number of atoms.

The correct option is B $H_2$.