Hola!
A sold an article to B at a loss of 20%, and B sold it to C at a profit of 20%. If A had sold the article for the price C paid, what would have been his loss or gain per cent?
Answer shouldn't be copied/Spammed.
Answers
Answered by
13
Step-by-step explanation:
given :
- A sold an article to B at a loss = 20 %
- C at a profit = 20%.
to find :
- what would have been his loss or gain per cent = ?
solution :
- A cost price = rs 100
- b selling price = rs 80
- loss 20% = (100 - 20/ 100 × 100)
- gain 20 % = (80+ 20/80 × 100)
- sell= rs 96
- then we have loss and gain = 4 %
learn more :
formula :
CP = ( SP × 100 ) / ( 100 – percentage loss ))
Gain % = (Gain / CP) × 100
Loss % = (Loss / CP) × 100
SP = [(100 + Gain%) / 100] × CP
SP = [(100 – Loss %) / 100] × CP
Answered by
11
Hi my friend! Here is your answer :
Given :
- loss incurred by A = 20%
- profit gained by B = 20 %
To find :
- if A had sold it to B at the price C had bought from B , then what would be the gain/loss percent of A ?
Let's Assume :
let's assume that the original CP of the article is rs.100 .
so, we will find other values depending on it .
Formula To be Applied :
we will use these formulae :
- Sp = Cp(100-loss%/100)
- Sp = Cp(100+profit%/100)
- profit/loss % = (p or l/cp)×100
Solution :
Cp at which A has bought the article (assumed) = 100
loss% = 20%
so, Sp in which he sold to B :
hence, the price A sold the article to B = 80
_____________________________________
So, The Cp for B = 80
Profit gained by B = 20%
So, Sp in which he sold to C :
hence, the B sold the article to C for 96
so, Cp or the price at C bought = 96
_____________________________________
so, if A had sold the article at this price, then
loss = cp-sp
or, loss = 100-96
or, loss = 4
so, A has incurred a loss of 4
loss% = loss/cp ×100
or, loss% = 4/100 × 100
or, loss % = 4%
hence, A's loss % would have been 4%
Similar questions