Question

HOLA.....

ASWER THIS PLZZ....

1.calculate the work done when 1.6 × 10^2 kg of oxygen at 300 kelvin is expanded isothermally and reversibly till its volume is divided.

R=8.3144×10^-3
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Answer 1

Explanation:

Molar mass of oxygen = 32 × 10−3Kg

Given mass of oxygen = 1.6 × 10−2 Kgno of moles = given massmolar mass = 1.6 × 10−232×10−3 = 0.5Work done = nRT lnVfViVf = 2ViT = 300 KR = 8.314 work done = −0.5 × 8.314 ×300 ln2ViVi = −864.42 Joule

Answer 2

Answer:

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