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Explain the Law of paired factor given by Mendel with an example .
Class - 10th
Chapter - Heredity and Evolution.
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Answers
In an experiment performed by Mendel, Breeding of pea plants differentiating with traits which gives rise to F1 generations which expresses the dominant trait, whereas the F2 generations express the traits into 3:1 ratio . The differentiated traits are :-
- Dominant traits
- Recessive traits
" The law of paired factor states the genes which splits into equal parts gametes ."
The progeny have an equal likelihood due to inheritance.
The second F2 generation its a monohybrid cross.
Result = Homozygous dominant, Heterozygous, or Homozygous recessive.
The genotypes are used to predict about offsprings .
He used a method known as a "Punnet Square Method ."
The homologous chromosomes break down into daughter nuclei .
An organism is diploid by two factors here.
It represents the same or alternate expressions .
Example :-
Crossing of two pea plant :-
Xy_______Xy
XX_______yy
It gives the pure tall pea plant XX & the pure dwarf pea plant yy.
Xy is in case of to hybridisation
_____________________________________
Monohybrid :
- Mendel took pea plants with different characters such as tall and short
- The progency produced from them where all tall so Mendel then allowed F1-generation plants go under self pollination.
- In F2-generation he found that not all plants tall, three quarter were tall and one quarter of them were short. This observation indicates that both both the traits of the tallness and shortness has inherited in F1-generation. But tallness trait were expressed in F1-generation
- Two copies of the trait are inherited in each sexually reproducing organism
- TT and Tt are phenotypically tall plants, whereas tt is a short plant. For a plant to be tall, the single copy of 'T' is a dominant trait while 't' is a recessive trait. In F2-generation, both the characters are recovered, through one of these is not seen in F1 stage. During gamete formation, the factor or allele of a pair segregate from each other .
F1 = (TT) × (tt) = (Tt)(Tt)(Tt)(Tt)
F2 = (Tt) × (Tt) = (TT)(Tt)(Tt)(tt)
Genotyphic ratio for F1 Generation = 1:1:1:1
Genotyphic ratio for F2 Generation = 1:2:1
Phenotypic ratio for F2 Generation = 3:1