Math, asked by HA7SH, 3 months ago

Hola brainly wizards,

Question:-

Q. A wall of length 10m wad to be built across an open ground . the height of the wall is 4m and thickness of the wall is 24cm. If this wall is to be built up with bricks whose dimensions are 24cm × 12cm × 8cm, how many bricks would be required.

Please don't spam....!!!​

Answers

Answered by itsmedevil07
3

Answer:

Bro your answer is 4166.67

Step-by-step explanation:

length of the wall, l = 10 m = 100 cm

Breadth of the wall, b = 42 m = 4200 cm

Height of the wall, h = 5 m = 500 cm

Volume of the wall = l × b × h = 100 cm × 4200 cm × 500 cm = 21000000 cm3

Dimension of the brick = 42 cm × 12 cm × 10cm

∴ Volume of each brick = 42 cm × 12cm × 10 cm = 5040 cm3

Let the number of bricks required be n.

n × Volume of each brick = Volume of the wall

therefore, n= vol of the wall/ vol of each brick

n= 21000000cm³/5040cm³

n= 4166.67

Thus, the number of brick required is 4166.67

Answered by Anonymous
71

Answer:

Explanation:

Given :

[ For wall ]

  • Length (l) = 10 m ⇒ 1000 cm
  • Height (h) = 4 m ⇒ 400 cm
  • Breadth (b) = 24 cm

[ For brick ]

  • Length (l) = 24 cm
  • Breadth (b) = 12 cm
  • Height (h) = 8 cm

To Find :

  • Number of bricks required.

Solution :

★Volume of wall,

Length × Breadth × height

⇒ 1000 × 24 × 400

⇒ 1000 × 9600

9600000 cm^3

★Volume of brick,

Length × Breadth × height

⇒ 24 × 12 × 8

⇒ 24 × 96

2304 cm^3

★Number of bricks,

Volume of wall / Volume of brick

⇒ 9600000 cm^3 / 2304 cm^3

⇒ 9600000 / 2304

4166.6

Hence, Number of bricks is 4166.6 .

Similar questions