hola friends here's the quest for you , solve the question in attachment, max 20 points, best will be the BRAINLIEST,.
so ✨✨ALL THE BEST✨✨✨
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*****hii mate****
HERE IS YOUR ANSWER ⬇️⬇️⬇️⬇️
The angle can be find just by finding the vertical component and horizontal component of velocity with which it will hit the ground.
So,considering for vertical motion,velocity after 10s will be,
v=0+gt (as,initially downward component of velocity was zero)
so,v=9.8⋅10=98ms−1
Now,horizontal component of velocity remains constant through out the motion i.e 98ms−1 (as because this velocity was imparted to the object while releasing from the plane moving with this amount of velocity)
So,angle made with the ground while hitting is tan−1(98/98)=45∘
may it help you
HERE IS YOUR ANSWER ⬇️⬇️⬇️⬇️
The angle can be find just by finding the vertical component and horizontal component of velocity with which it will hit the ground.
So,considering for vertical motion,velocity after 10s will be,
v=0+gt (as,initially downward component of velocity was zero)
so,v=9.8⋅10=98ms−1
Now,horizontal component of velocity remains constant through out the motion i.e 98ms−1 (as because this velocity was imparted to the object while releasing from the plane moving with this amount of velocity)
So,angle made with the ground while hitting is tan−1(98/98)=45∘
may it help you
shubhi12397:
thank you
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B)
45°
This is the correct answer?! hi
45°
This is the correct answer?! hi
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