Math, asked by Amankanojia1980, 11 months ago

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solve this Q​

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Answered by dharshanraghuraman20
0

Answer:

Step-by-step explanation:

Volume of the pole = 22/7 x 0.1 x 7

= 2.2mcube

Weight of the pole = 225x2.2

= 495kg

Therefore the weight of the pole is 495kg

Answered by rishu6845
1

Answer:

49.5kg

Step-by-step explanation:

Given---> Height of pole = 7m

Diameter of pole = 20cm

Weight of wood per m³ = 225 kg

Solution---> ATQ,

Height of pole = 7m

Diameter of pole = 20cm

Radius of pole = diameter of pole / 2

= 20 / 2 = 10 cm

= 10 / 100 = 0.1 m

Volume of cylinder = π r² h

= ( 22/7 ) × ( 0.1 )² × 7

= ( 22 ) × ( 0.01 )

= 0.22 m³

ATQ, weight per m³ = 225 kg

So, weight of pole = 225 × 0.22

= 49.5 kg

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