Math, asked by Jeniyaa, 1 year ago

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Answers

Answered by Anonymous
104

Hey Miss

Here's the answer

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Solution 4 :-

=> We can write

19π/3

= 6π + π/3

So

=> Sin ( 19π/3 )

=> Sin ( 6π + π/3 )

we know

Sin ( π + ∅ ) = sin ∅

=> sin ( π/3 )

=> √3/2

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Solution 5 :-

Sin ( -1125° )

We know

Sin (-∅ ) = - sin (∅ )

=> - sin( 1125° )

=> - sin ( 3×360 + 45 )

We know

sin ( 360 + ∅ ) = sin ∅

=> - sin ( 45 )

=> - 1/√2

HOPE HELPED

PEACE :)


Jeniyaa: thanks dear..
Anonymous: my pleasure :)
Sristisen: you helped
Anonymous: :)
deepsen640: wow great answer
Juhita16: awesome !
RaGhAv200407: which class question is this??
Answered by pranav2001
90

sin(19π/3 ) = sin( 6π + π/3) = sin( π/3 )

√3/2

now

sin ( -1125 )

- sin ( 3× 360 + 45 )

- Sin(45 )

-1/√2


Jeniyaa: thanks dear..
PARI9111: ty
RaGhAv200407: what class question is this
Jeniyaa: class 11
RaGhAv200407: chapter?
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