Question

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Answer 1

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Answer 2

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$\large\red{Question:}$

$2 cosec^{2} 30 +3 sin^{2} 60 -\frac{3}{4} tan^{2} 30$



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We have ,
$cosec\: 30 = 2$

$sin\: 60 =\frac{\sqrt{3}}{2}$

$tan\: 30 = \frac{1}{\sqrt{3}}$


Substitute the values in question

$2 (2)^{2}+3 (\frac{\sqrt{3}}{2})^{2} -\frac{3}{4} (\frac{1}{\sqrt{3}})^{2}$

$2(4) + 3(\frac{3}{4})- (\frac{3}{4}× \frac{1}{3})$

$8 + (\frac{9}{4})- (\frac{3}{12})$

$8 + (\frac{9}{4})- (\frac{1}{4})$

$8 + (\frac{8}{4})$

$8 + (2)$

$10$


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