hola guys......
plz answer these questions in the attachment....
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Hola user!!!
Let 3:5:9:13 be 3x, 5x, 9x, 13x
Sum of a quadrilateral = 360°
3x + 5x + 9x + 13x = 360°
30x = 360°
x = 360/30
x = 12°
3x = 3 × 12 = 36°
5x = 5 × 12 = 60°
9x = 9 × 12 = 108°
13x = 13 × 12 = 156°
#be brainly
Let 3:5:9:13 be 3x, 5x, 9x, 13x
Sum of a quadrilateral = 360°
3x + 5x + 9x + 13x = 360°
30x = 360°
x = 360/30
x = 12°
3x = 3 × 12 = 36°
5x = 5 × 12 = 60°
9x = 9 × 12 = 108°
13x = 13 × 12 = 156°
#be brainly
Answered by
2
let angels in ratio 3:5:9:13 be a, b,c,d
let
a=3x, b=5x, c=9x, d=13x
where x is a any number...
as we know that
sum of angels of quardrilateral is 360degree
now,
a+b+c+d=360degree
or,3x+5x+9x+13x=360degree
or,
30x=360degree
or
x=360/30=12degree
so x=12degree....
now you can solve easily
hope you like it
let
a=3x, b=5x, c=9x, d=13x
where x is a any number...
as we know that
sum of angels of quardrilateral is 360degree
now,
a+b+c+d=360degree
or,3x+5x+9x+13x=360degree
or,
30x=360degree
or
x=360/30=12degree
so x=12degree....
now you can solve easily
hope you like it
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