Math, asked by Anonymous, 8 months ago

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Today's Question?
Solve the following pair of linear equations:-
(1)2/3+2/3y=1/6
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Answers

Answered by Anonymous
7

Given,

x + y = 3……. (i)

2x + 5y = 12……. (ii)

For equation (i),

When y = 0, we have x =3

When x= 0, we have y =3

Thus we have the following table giving points on the line x + y = 3

x

0

3

y

3

0

For equation (ii),

We solve for y:

⇒ y = (12 – 2x)/5

So, when x = 1

y = (12 – 2(1))/5 = 2

And, when x = 6

⇒ y = (12 – 2(6))/5 = 0

Thus we have the following table giving points on the line 2x + 5y = 12

x

1

6

y

2

0

Graph of the equations (i) and (ii) is as below:

Clearly the two lines intersect at a single point P (1, 2)

Hence, x= 1 and y = 2

Attachments:
Answered by anushkasharma8840
8

Step-by-step explanation:

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