Question

Hola guysssssssss............. ​

Answer 1

Answer:

Hlo mate... ☺☺☺

See the attachment.. ✌✌

Answer 2

hi dear here iš ur answer

_____******_________

solution:-

Self inductance of a coil, L = μᵣμ₀n² Al

Where μᵣ is the relative permittivity of the coil, n is the number of terms per unit length, A is the area of cross-section, l is the length of the solenoid

L ∝ n²

Self inductance of 500 turns coil = 125 mH Therefore, L for the coil of 800 turns = [125 / (500)²] × 800² L

= 320 mH

______******___________

hope it is helpfull:-D

have a great day^_^