Question

hola , help help .......................................​

Answer 1

To find :—

• Dencity of the packet.
• Mass of the packet.

Formula applied :—

$dencity = \frac{mass}{volume}$

Solution :—

Here, Mass of packet = 500 g

And, Volume of packet = 350 cm³

Now,

$dencity \: of \: packet = \frac{mass \: of \: packet}{volume \: of \: packet}$

$= \frac{500 \: g}{350 \: {cm}^{3} }$

$= 1.42 \: g \: {cm}^{3}$

Since the dencity of packet (1.42 g cm³) is more than the dencity of water (1 g cm-³), therefore , the packet will sink in water.

The packet which sink in water will displace water equal to its own volume. Since the volume of the packet is 350 cm³, so it will displace 350 cm³ of water. We have now to calculate the mass of 350 cm³ of water.

Now,

$dencity \: of \: water = \frac{mass \: of \: water}{volume \: of \: water}$

So,

$1 \: g \: {cm}^{ - 3} = \frac{mass \: of \: water}{350 {cm}^{3} }$

And,

$mass \: of \: water = 1 \: g {cm}^{3} \times 350 {cm}^{3}$

$= 350 \: g$

Thus, the mass of water displaces by the packet is 350 grams.