Question

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here is another question
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Prove that sin²A+cos²A=1 ​

Answer 1

Answer:

a²+b² =c²

let say a=x and b=y

picture helps,

draw a triangle on a plane, with angle theta, with hypotenuse c (let's say c=r)

x (adjacent side) over r will be cos(theta)

as well as y(opposite side of theta) over r will be sin(theta)

therefore, x^2 + y^2 = r^2

if you divide both sides by r^2 you have x^2/r^2 +y^2/r^2 = 1

since x^2/r^2 = cos^theta, and y^2/r^2=sin^2theta then

x^2/r^2 +y^2/r^2 = 1 will be cos^2theta +sin^theta = 1

which is the same as sin^2theta +cos^2theta = 1

or y^2/r^2 + x^2/r^2 = 1

Answer 2

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