Question

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a gun of mass 10 kg fires 4 bullets per second. the mass of each bullet is 20 grams. and the velocity of bullet when it leaves the gun is 300 metre per second the force required to hold the gun while firing is???


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Answer 1

Hii !

Solution :-

Given :- gun mass =M1= 10Kg = 10*1000 = 10000gram

bullets mass = M2= 20Gram

velocity of bullets =v1 = 300m/s

Time = 1sec

velocity of gun = V2 = ?

*using law of conservation of momentum*

m1v1 = m2v2

10*1000 × V1 = 20 ×4× 300

V1 = 24000/10000

V1 = 24/10

v1 = 2.4hence, velocity of gun is 2.4 m/s

•°•force = m×a = 10 ×(vf-vi)/t

= 10 × (2.4-0)/1 = 10×2.4 =24N answer

Force required to hold the gun while firing is 24N . ✔

Hope it helps you !!

@Raj❤✔✔