Question

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A welding fuel gas contains carbon and hydrogen only . Burning a small sample of it in oxygen gives 3.38 g carbon dioxide , 0.690 g of water and no other products . A volume of 10.0 L (measured at STP) of this welding gas is found to weight 11.6 g, calculate

i) Emperical formula

ii) Molar mass of the gas

iii) Molecular formula

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Answer 1

Answer:

Molar mass is 25.984

Rest i am solving dear..

See the moles formed of CO2 are 0.076 and that of H2O are 0.038

Emperical formula=(Molecular mass÷molecular weight of oxygen) × 8gram

Or

Emperical formula =( M÷O) ×5.6litre