Chemistry, asked by Asha73, 1 year ago

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An ion with mass number 37 possesses one unit of negative charge. If the ion contains 11.1% more neutrons than the electrons , find the symbol of the ion?

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Answers

Answered by AdithyaMahesh17
1

Explanation:

Chlorine's mass number is 37.

The ion is Cl^-

No. of neutrons = A - Z

= 37 - 17

= 20

No. of electrons in Chlorine ion is 18.

Symbol of the element is Cl

Answered by Anonymous
5

ᴇᴀᴜsᴜʀᴇ ʜᴇʀᴇ

Let the number of electrons in the ion carrying a negative charge be x.

Then,

Number of Neutrons Present

= x + 11.1% of x

= x + 0.111 x

= 1.111 x

Number of Electrons in the Neutral Atom = (x – 1)

(When an ion carries a negative charge, it carries an extra electron)

∴ Number of Protons in the Neutral Atom = x – 1

Therefore ,

37 = 1.111x + x -1

Or 2.111 x = 38

Or x = 18

Therefore no. of protons = Atomic no.

= x -1 = 18 – 1 = 17

∴The symbol of the ion is 

 {}^{37} 17Cl {}^{ - 1}

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